What is the derivative of 49y^6-84y^3+36 ?

The derivative of 49y^6-84y^3+36 is 294y^5-252y^2

What is the first derivative of 49y^6-84y^3+36 ?

The first derivative of 49y^6-84y^3+36 is 294y^5-252y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

49 y^{6} - 84 y^{3} + 36

294 y^{5} - 252 y^{2}

Solution steps

\frac{d}{d y} (49 y^{6} - 84 y^{3} + 36)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (49 y^{6}) - \frac{d}{d y} (84 y^{3}) + \frac{d}{d y} (36)

\frac{d}{d y} (49 y^{6}) = 294 y^{5}

\frac{d}{d y} (84 y^{3}) = 252 y^{2}

\frac{d}{d y} (36) = 0

= 294 y^{5} - 252 y^{2} + 0

Simplify

= 294 y^{5} - 252 y^{2}

\int \frac{3}{x ( x ^{4} + 7 )} d x

\int e^{7 x + 8} d x

\int (e^{x} sin (y) - y) d x

ln (tan^{2} (x))

y = x, y = x^{2} - 2, y = 0

What is the derivative of 49y^6-84y^3+36 ?
The derivative of 49y^6-84y^3+36 is 294y^5-252y^2
What is the first derivative of 49y^6-84y^3+36 ?
The first derivative of 49y^6-84y^3+36 is 294y^5-252y^2