What is the integral from 9 to infinity of 2/(x^3) ?

The integral from 9 to infinity of 2/(x^3) is 1/81

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 9 to infinity of 2/(x^3)

\int_{9}^{\infty} \frac{2}{x ^{3}} d x

\frac{1}{81}

Decimal Notation

0.01234 \dots

Solution steps

\int_{9}^{\infty} \frac{2}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{2}{x ^{3}} d x = - \frac{1}{x ^{2}} + C

Compute the boundaries:

\int_{9}^{\infty} \frac{2}{x ^{3}} d x = 0 - (- \frac{1}{81})

= 0 - (- \frac{1}{81})

Simplify

= \frac{1}{81}

(y e^{x y} - \frac{1}{y}) d x (x e^{x y} - \frac{x}{y ^{2}}) d y = 0

f (x) = \frac{5 t + 300}{t ^{2} + 25}

2 x^{3} + 4 x

\int x^{2} y^{2} d x

(- 7 x^{2} + 7)^{5} (- 7 x^{2} + 4)^{- 4}

What is the integral from 9 to infinity of 2/(x^3) ?
The integral from 9 to infinity of 2/(x^3) is 1/81