What is the derivative of 2x^3+4x ?

The derivative of 2x^3+4x is 6x^2+4

What is the first derivative of 2x^3+4x ?

The first derivative of 2x^3+4x is 6x^2+4

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derivative of

2 x^{3} + 4 x

6 x^{2} + 4

Solution steps

\frac{d}{d x} (2 x^{3} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x) = 4

= 6 x^{2} + 4

\int x^{2} y^{2} d x

(- 7 x^{2} + 7)^{5} (- 7 x^{2} + 4)^{- 4}

ln (1 + 4 x)

\int_{1}^{2} \frac{x ^{4}}{8} + \frac{1}{4 x ^{2}} d x

What is the derivative of 2x^3+4x ?
The derivative of 2x^3+4x is 6x^2+4
What is the first derivative of 2x^3+4x ?
The first derivative of 2x^3+4x is 6x^2+4