What is the solution for (dy)/(dx)+x^2(3y-2)=0 ?

The solution for (dy)/(dx)+x^2(3y-2)=0 is y=(e^{-x^3+c_{1}})/3+2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+x^2(3y-2)=0

\frac{d y}{d x} + x^{2} (3 y - 2) = 0

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{2}{3}

Solution steps

\frac{d y}{d x} + x^{2} (3 y - 2) = 0

Solve separable ODE:

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{2}{3}

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{2}{3}

\int x^{6} d x

\frac{d}{d x} (\frac{( 1 - x )}{1 + x})

\frac{d}{d x} (9 - 6 x)

\int (- 4 sin (2 x) + 3 cos (3 x)) d x

x^{2} e^{19 x}

What is the solution for (dy)/(dx)+x^2(3y-2)=0 ?
The solution for (dy)/(dx)+x^2(3y-2)=0 is y=(e^{-x^3+c_{1}})/3+2/3