What is the derivative of sqrt(9-6x) ?

The derivative of sqrt(9-6x) is -3/(sqrt(9-6x))

What is the first derivative of sqrt(9-6x) ?

The first derivative of sqrt(9-6x) is -3/(sqrt(9-6x))

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\frac{d}{d x} (9 - 6 x)

- \frac{3}{9 - 6 x}

Solution steps

\frac{d}{d x} (9 - 6 x)

Apply the chain rule:

\frac{1}{2 9 - 6 x} \frac{d}{d x} (9 - 6 x)

= \frac{1}{2 9 - 6 x} \frac{d}{d x} (9 - 6 x)

\frac{d}{d x} (9 - 6 x) = - 6

= \frac{1}{2 9 - 6 x} (- 6)

Simplify

\frac{1}{2 9 - 6 x} (- 6) : - \frac{3}{9 - 6 x}

= - \frac{3}{9 - 6 x}

\int (- 4 sin (2 x) + 3 cos (3 x)) d x

x^{2} e^{19 x}

\frac{2 x ^{5} + 6}{x ^{3}}

x^{2}, x + 2, 2, - 1

\int - 5 x^{5} e^{x^{6}} d x

What is the derivative of sqrt(9-6x) ?
The derivative of sqrt(9-6x) is -3/(sqrt(9-6x))
What is the first derivative of sqrt(9-6x) ?
The first derivative of sqrt(9-6x) is -3/(sqrt(9-6x))