What is the d/(dθ)(3cos(θ)-4sin(θ)) ?

The d/(dθ)(3cos(θ)-4sin(θ)) is -3sin(θ)-4cos(θ)

What is the first d/(dθ)(3cos(θ)-4sin(θ)) ?

The first d/(dθ)(3cos(θ)-4sin(θ)) is -3sin(θ)-4cos(θ)

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\frac{d}{d θ} (3 cos (θ) - 4 sin (θ))

- 3 sin (θ) - 4 cos (θ)

Solution steps

\frac{d}{d θ} (3 cos (θ) - 4 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (3 cos (θ)) - \frac{d}{d θ} (4 sin (θ))

\frac{d}{d θ} (3 cos (θ)) = - 3 sin (θ)

\frac{d}{d θ} (4 sin (θ)) = 4 cos (θ)

= - 3 sin (θ) - 4 cos (θ)

y = x^{4}, x = y^{7}, x = 0, x = 1

\int_{0}^{1} arctan (x) d x

\frac{\partial}{\partial x} ((x - 2)^{2} + (y - 2)^{2})

\int e^{x} + e d x

y = - 2 t^{2} + 3 t - 6

What is the d/(dθ)(3cos(θ)-4sin(θ)) ?
The d/(dθ)(3cos(θ)-4sin(θ)) is -3sin(θ)-4cos(θ)
What is the first d/(dθ)(3cos(θ)-4sin(θ)) ?
The first d/(dθ)(3cos(θ)-4sin(θ)) is -3sin(θ)-4cos(θ)