What is the integral of (4x^3+2xy^2) ?

The integral of (4x^3+2xy^2) is x^4+y^2x^2+C

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integral of (4x^3+2xy^2)

\int (4 x^{3} + 2 x y^{2}) d x

x^{4} + y^{2} x^{2} + C

Solution steps

\int 4 x^{3} + 2 x y^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} d x + \int 2 y^{2} x d x

\int 4 x^{3} d x = x^{4}

\int 2 y^{2} x d x = y^{2} x^{2}

= x^{4} + y^{2} x^{2}

Add a constant to the solution

= x^{4} + y^{2} x^{2} + C

x^{2} y^{^{'}} + 2 x y = ln (x)

\int \frac{x}{2 x + 3} d x

f (x) = \frac{x}{7 x ^{2} + 1}

\frac{x + 1}{x ^{3} + x - 2}

\frac{d y}{d t} = - \frac{1}{5} y

What is the integral of (4x^3+2xy^2) ?
The integral of (4x^3+2xy^2) is x^4+y^2x^2+C