What is the sum from n=0 to infinity of 5/(pi^n) ?

The sum from n=0 to infinity of 5/(pi^n) is 5*pi/(pi-1)

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sum from n=0 to infinity of 5/(pi^n)

n = 0 \sum \infty \frac{5}{π ^{n}}

5 \cdot \frac{π}{π - 1}

Solution steps

n = 0 \sum \infty \frac{5}{π ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 0 \sum \infty \frac{1}{π ^{n}}

Apply Series Geometric Test:

\frac{π}{π - 1}

= 5 \cdot \frac{π}{π - 1}

(4 x^{3})^{^{'}}

\frac{d}{d x} (4 + 2 x - 3 x^{2} - 5 x^{3} - 8 x^{4} + 9 x^{5})

lo g_{5} (7 x + 3)

\int x (3 + 4 x)^{4} d x

\frac{x ^{4} + 1}{y} \frac{d y}{d x} = - \frac{x ^{3}}{4}

What is the sum from n=0 to infinity of 5/(pi^n) ?
The sum from n=0 to infinity of 5/(pi^n) is 5*pi/(pi-1)