What is the derivative of 3x^4-6x^3+1 ?

The derivative of 3x^4-6x^3+1 is 12x^3-18x^2

What is the first derivative of 3x^4-6x^3+1 ?

The first derivative of 3x^4-6x^3+1 is 12x^3-18x^2

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derivative of

3 x^{4} - 6 x^{3} + 1

12 x^{3} - 18 x^{2}

Solution steps

\frac{d}{d x} (3 x^{4} - 6 x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (6 x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (1) = 0

= 12 x^{3} - 18 x^{2} + 0

Simplify

= 12 x^{3} - 18 x^{2}

f (x) = \frac{x ^{2} + 8}{9 x - 2}

\frac{d}{d x} (x arccos (x) - 1 - x^{2})

x^{10} e^{x}

e^{\frac{x}{2}}

\frac{d}{d x} (ux)

What is the derivative of 3x^4-6x^3+1 ?
The derivative of 3x^4-6x^3+1 is 12x^3-18x^2
What is the first derivative of 3x^4-6x^3+1 ?
The first derivative of 3x^4-6x^3+1 is 12x^3-18x^2