What is laplacetransform-5e^{2t} ?

The answer to laplacetransform-5e^{2t} is -5/(s-2)

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laplacetransform-5e^{2t}

laplace transform

- 5 e^{2 t}

- \frac{5}{s - 2}

Solution steps

L {- 5 e^{2 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {e^{2 t}}

L {e^{2 t}} : \frac{1}{s - 2}

= - 5 \cdot \frac{1}{s - 2}

Refine

- 5 \frac{1}{s - 2} : - \frac{5}{s - 2}

= - \frac{5}{s - 2}

((x - 4)^{2})^{^{'}}

n = 1 \sum \infty n! (x - 1)^{n}

\int_{1}^{4} x^{2} - 3 x d x

\int_{0}^{4} \frac{x}{x ^{2} - 1} d x

\frac{\partial}{\partial x} (3 x + 2 y - 3)

What is laplacetransform-5e^{2t} ?
The answer to laplacetransform-5e^{2t} is -5/(s-2)