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Popular >

y^'=y^2+y

Solution

y^{^{'}} = y^{2} + y

Solution

y = \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

Solution steps

y^{'} (t) = y^{2} + y

Solve separable ODE:

y = \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

y = \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

Popular Examples

derivative of (3x+2^6)

\frac{d}{d x} ((3 x + 2)^{6})

integral from-7 to 7 of 1/x

\int_{- 7}^{7} \frac{1}{x} d x

limit as x approaches 2 of 3ln(x-1)

x \to 2 lim (3 ln (x - 1))

tangent of y= x/(sqrt(9+x^2)),(0,0)tangent of

y = \frac{x}{9 + x ^{2}}, (0, 0)

integral of 40sin((pix)/3)+50

\int 40 sin (\frac{π x}{3}) + 50 d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2+y ?
The solution for y^'=y^2+y is y=(e^{t+c_{1}})/(1-e^{t+c_{1)}}