What is the solution for 2y^{''}+5y^'-3y=0,y(0)=3,y^'(0)=19 ?

The solution for 2y^{''}+5y^'-3y=0,y(0)=3,y^'(0)=19 is y=8e^{t/2}-5e^{-3t}

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2y^{''}+5y^'-3y=0,y(0)=3,y^'(0)=19

2 y^{^{''}} + 5 y^{^{'}} - 3 y = 0, y (0) = 3, y^{^{'}} (0) = 19

y = 8 e^{\frac{t}{2}} - 5 e^{- 3 t}

Solution steps

2 y^{''} (t) + 5 y^{'} (t) - 3 y = 0

Solve linear ODE:

y = 8 e^{\frac{t}{2}} - 5 e^{- 3 t}

y = 8 e^{\frac{t}{2}} - 5 e^{- 3 t}

f (x) = \frac{7}{8 t ^{4}}

f (x) = 2 x^{3} - x^{2} + 2, at x = 1

\int ln (t) d t

\frac{d}{d x} (ln (2 - 3 x))

11 x, x^{2} - 12

What is the solution for 2y^{''}+5y^'-3y=0,y(0)=3,y^'(0)=19 ?
The solution for 2y^{''}+5y^'-3y=0,y(0)=3,y^'(0)=19 is y=8e^{t/2}-5e^{-3t}