What is the derivative of ln(2-3x) ?

The derivative of ln(2-3x) is -3/(2-3x)

What is the first derivative of ln(2-3x) ?

The first derivative of ln(2-3x) is -3/(2-3x)

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\frac{d}{d x} (ln (2 - 3 x))

- \frac{3}{2 - 3 x}

Solution steps

\frac{d}{d x} (ln (2 - 3 x))

Apply the chain rule:

\frac{1}{2 - 3 x} \frac{d}{d x} (2 - 3 x)

= \frac{1}{2 - 3 x} \frac{d}{d x} (2 - 3 x)

\frac{d}{d x} (2 - 3 x) = - 3

= \frac{1}{2 - 3 x} (- 3)

Simplify

\frac{1}{2 - 3 x} (- 3) : - \frac{3}{2 - 3 x}

= - \frac{3}{2 - 3 x}

11 x, x^{2} - 12

(- 1, - 1), (0, 0)

sin (x + \frac{π}{2})

y^{^{'}} = \frac{y ^{2} + 2 x y}{x ^{2}}

\int_{0}^{\frac{π}{2}} 4 cos^{5} (x) d x

What is the derivative of ln(2-3x) ?
The derivative of ln(2-3x) is -3/(2-3x)
What is the first derivative of ln(2-3x) ?
The first derivative of ln(2-3x) is -3/(2-3x)