What is (\partial)/(\partial x)(2x^2+9y^2+3) ?

The answer to (\partial)/(\partial x)(2x^2+9y^2+3) is 4x

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(\partial)/(\partial x)(2x^2+9y^2+3)

\frac{\partial}{\partial x} (2 x^{2} + 9 y^{2} + 3)

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + 9 y^{2} + 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (9 y^{2}) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (9 y^{2}) = 0

\frac{\partial}{\partial x} (3) = 0

= 4 x + 0 + 0

Simplify

= 4 x

\frac{d}{d x} (2 x^{3} + 4 x - 2)

4 x^{3} - 16 x

\frac{d x}{d t} - 4 x = cos (4 t)

\int 8 sin (- 2 t + 7) d t

(- 3) (0.1)

What is (\partial)/(\partial x)(2x^2+9y^2+3) ?
The answer to (\partial)/(\partial x)(2x^2+9y^2+3) is 4x