What is the tangent of y=(sqrt(x))/(x+5),(4, 2/9) ?

The tangent of y=(sqrt(x))/(x+5),(4, 2/9) is y= 1/324 x+17/81

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tangent of y=(sqrt(x))/(x+5),(4, 2/9)

tangent of

y = \frac{x}{x + 5}, (4, \frac{2}{9})

y = \frac{1}{324} x + \frac{17}{81}

Solution steps

Find the slope of

y = \frac{x}{x + 5} : \frac{d y}{d x} = \frac{- x + 5}{2 x ( x + 5 ) ^{2}}

Compute the slope of

y = \frac{x}{x + 5}

(4, \frac{2}{9}) : m = \frac{1}{324}

Find the line with slope m=

\frac{1}{324}

and passing through

(4, \frac{2}{9}) : y = \frac{1}{324} x + \frac{17}{81}

y = \frac{1}{324} x + \frac{17}{81}

y^{^{'}} + y^{2} sin (t) = 0

\int e^{- 10 t} d t

\frac{\partial}{\partial y} (x^{2} + y^{3})

\frac{d}{d x} (\frac{1 - 4 x}{5 + x})

\frac{d}{d x} (3 x^{2} - 4 x + 6)

What is the tangent of y=(sqrt(x))/(x+5),(4, 2/9) ?
The tangent of y=(sqrt(x))/(x+5),(4, 2/9) is y= 1/324 x+17/81