What is area x=y^2,x=y+2[0,4] ?

The answer to area x=y^2,x=y+2[0,4] is No Solution

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area x=y^2,x=y+2[0,4]

area

x = y^{2}, x = y + 2 [0, 4]

No Solution

Solution steps

Isolate

y

for

x = y^{2} : y = x, y = - x

Isolate

y

for

x = y + 2 [0, 4] : y = x - 2 [0, 4]

f_{1} (x) = x

f_{2} (x) = - x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = - x : x = 0

x = x - 2 [0, 4] :

No Solution for

x \in R

- x = x - 2 [0, 4] :

No Solution for

x \in R

Curves not bounded

= No Solution

\frac{d}{d x} (x^{5} + x^{7} + x^{9})

x \to + 2 lim (3 x - 9)

\int x^{2} + 4 x + 13 d x

y = 5 cos (x), y = 5 sin (x)

\int - \frac{2}{x + 2} d x

What is area x=y^2,x=y+2[0,4] ?
The answer to area x=y^2,x=y+2[0,4] is No Solution