What is the tangent of f(x)=7x-x^2,\at x=1 ?

The tangent of f(x)=7x-x^2,\at x=1 is y=5x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=7x-x^2,\at x=1

tangent of

f (x) = 7 x - x^{2}, at x = 1

y = 5 x + 1

Solution steps

Find the tangent point:

(1, 6)

Find the slope of

f (x) = 7 x - x^{2} : \frac{df ( x )}{d x} = 7 - 2 x

Compute the slope of

f (x) = 7 x - x^{2}

x = 1 : m = 5

Find the line with slope m=

5

and passing through

(1, 6) : y = 5 x + 1

y = 5 x + 1

(sin (2 t))^{^{'}}

\int_{0}^{π} 5 x^{2} sin (\frac{1}{2} x) d x

x \to 1 lim (9 x + 5)

t^{2} y^{^{''}} + t y^{^{'}} + 4 y = sin (2 ln (t))

\int - 5 tan^{5} (4 x) sec^{6} (4 x) d x

What is the tangent of f(x)=7x-x^2,\at x=1 ?
The tangent of f(x)=7x-x^2,\at x=1 is y=5x+1