What is the integral of x/(\sqrt[4]{x+4)} ?

The integral of x/(\sqrt[4]{x+4)} is 4/7 (x+4)^{7/4}-16/3 (x+4)^{3/4}+C

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integral of x/(\sqrt[4]{x+4)}

\frac{4}{7} (x + 4)^{\frac{7}{4}} - \frac{16}{3} (x + 4)^{\frac{3}{4}} + C

Solution steps

Apply u-substitution

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int u^{\frac{3}{4}} d u = \frac{4}{7} u^{\frac{7}{4}}

= \frac{4}{7} u^{\frac{7}{4}} - \frac{16}{3} u^{\frac{3}{4}}

Substitute back

u = x + 4

= \frac{4}{7} (x + 4)^{\frac{7}{4}} - \frac{16}{3} (x + 4)^{\frac{3}{4}}

Add a constant to the solution

= \frac{4}{7} (x + 4)^{\frac{7}{4}} - \frac{16}{3} (x + 4)^{\frac{3}{4}} + C

\frac{\partial}{\partial x} (x e^{y})

((e^{2 x} - 5 x)^{2})^{^{'}}

(1, 1), (3, - \frac{5}{6})

\int sin (3 x) sin (8 x) d x

f (x) = 3 x + 4, (4, 4)

What is the integral of x/(\sqrt[4]{x+4)} ?
The integral of x/(\sqrt[4]{x+4)} is 4/7 (x+4)^{7/4}-16/3 (x+4)^{3/4}+C