What is the tangent of f(x)=sqrt(3x+4),(4,4) ?

The tangent of f(x)=sqrt(3x+4),(4,4) is y= 3/8 x+5/2

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tangent of f(x)=sqrt(3x+4),(4,4)

tangent of

f (x) = 3 x + 4, (4, 4)

y = \frac{3}{8} x + \frac{5}{2}

Solution steps

Find the slope of

f (x) = 3 x + 4 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 4}

Compute the slope of

f (x) = 3 x + 4

(4, 4) : m = \frac{3}{8}

Find the line with slope m=

\frac{3}{8}

and passing through

(4, 4) : y = \frac{3}{8} x + \frac{5}{2}

y = \frac{3}{8} x + \frac{5}{2}

\int sin (4 x + 1) d x

\frac{\partial}{\partial y} (sin (y) sin (x))

x + y^{2} = 12, x + y = 0

\int tan^{5} (2 x) sec^{4} (2 x) d x

\int \frac{1}{t ^{2} - 4 t + 29} d t

What is the tangent of f(x)=sqrt(3x+4),(4,4) ?
The tangent of f(x)=sqrt(3x+4),(4,4) is y= 3/8 x+5/2