What is the derivative of 4cos(t) ?

The derivative of 4cos(t) is -4sin(t)

What is the first derivative of 4cos(t) ?

The first derivative of 4cos(t) is -4sin(t)

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derivative of

4 cos (t)

- 4 sin (t)

Solution steps

\frac{d}{d t} (4 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 4 (- sin (t))

Simplify

= - 4 sin (t)

x = 4 y^{2}, x = 2 + 2 y^{2}

\frac{\partial}{\partial x} (4 x^{2} + x y + 3 y^{2} - 8)

\int sin (x) sec^{2} (cos (x)) d x

f (x) = 2 x^{2}, at x = 5

\int 7 cos^{2} (x) sin (2 x) d x

What is the derivative of 4cos(t) ?
The derivative of 4cos(t) is -4sin(t)
What is the first derivative of 4cos(t) ?
The first derivative of 4cos(t) is -4sin(t)