What is the tangent of f(x)=e^x,\at x=ln(13) ?

The tangent of f(x)=e^x,\at x=ln(13) is y=13x+13-13ln(13)

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tangent of f(x)=e^x,\at x=ln(13)

tangent of

f (x) = e^{x}, at x = ln (13)

y = 13 x + 13 - 13 ln (13)

Solution steps

Find the tangent point:

(ln (13), 13)

Find the slope of

f (x) = e^{x} : \frac{df ( x )}{d x} = e^{x}

Compute the slope of

f (x) = e^{x}

x = ln (13) : m = 13

Find the line with slope m=

13

and passing through

(ln (13), 13) : y = 13 x + 13 - 13 ln (13)

y = 13 x + 13 - 13 ln (13)

f (x) = e^{x} (8 + 3 x + 5 x^{2}), at x = 0

\frac{d}{d x} (x^{3} e^{- 4 x})

\frac{d y}{d x} + y - 4 cos (x) = 0

\int_{0}^{5} \frac{1}{x ^{\frac{17}{18}}} d x

\int v e^{uv} d u

What is the tangent of f(x)=e^x,\at x=ln(13) ?
The tangent of f(x)=e^x,\at x=ln(13) is y=13x+13-13ln(13)