What is the solution for y^'=0.0875-(7y)/(2000),y(0)=50 ?

The solution for y^'=0.0875-(7y)/(2000),y(0)=50 is y=25+(25)/(e^{\frac{7t){2000}}}

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y^'=0.0875-(7y)/(2000),y(0)=50

y^{^{'}} = 0.0875 - \frac{7 y}{2000}, y (0) = 50

y = 25 + \frac{25}{e ^{\frac{7 t}{2000}}}

Solution steps

y^{'} (t) = 0.0875 - \frac{7 y}{2000}

Solve linear ODE:

y = 25 + \frac{25}{e ^{\frac{7 t}{2000}}}

y = 25 + \frac{25}{e ^{\frac{7 t}{2000}}}

f (x) = \frac{( 3 x + 5 )}{1 + x}, at x = 1

\frac{d}{d x} (3 x^{2} - 6 x - 8)

\int \frac{e ^{x}}{x - 1} d x

x \to 0 lim (ln (1 - 5 x))

x y^{^{''}} - y^{^{'}} + y^{^{'}} = 0

What is the solution for y^'=0.0875-(7y)/(2000),y(0)=50 ?
The solution for y^'=0.0875-(7y)/(2000),y(0)=50 is y=25+(25)/(e^{\frac{7t){2000}}}