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Popular >

xy^{''}-y^'+y^'=0

Solution

x y^{^{''}} - y^{^{'}} + y^{^{'}} = 0

Solution

y = c_{1} x + c_{2}

Solution steps

x y^{''} (x) - y^{'} (x) + y^{'} (x) = 0

Isolate

y^{''} (x) : y^{''} (x) = 0

Solve

y^{''} (x) = 0 : y^{'} (x) = c_{1}

Solve

y^{'} (x) = c_{1} : y = c_{1} x + c_{2}

y = c_{1} x + c_{2}

Popular Examples

derivative of (1+x-4sqrt(x)/x)

\frac{d}{d x} (\frac{1 + x - 4 x}{x})

derivative of y=ln(3x^5)derivative of

y = ln (3 x^{5})

(dy)/(dx)+2y=2e^x

\frac{d y}{d x} + 2 y = 2 e^{x}

derivative of x^2sqrt(10x-3)

\frac{d}{d x} (x^{2} 10 x - 3)

3y^{''}+17y^'+10y=0

3 y^{^{''}} + 17 y^{^{'}} + 10 y = 0

Frequently Asked Questions (FAQ)

What is the solution for xy^{''}-y^'+y^'=0 ?
The solution for xy^{''}-y^'+y^'=0 is y=c_{1}x+c_{2}