What is the solution for (dy)/(dx)+2y=2e^x ?

The solution for (dy)/(dx)+2y=2e^x is y=(2e^x)/3+(c_{1})/(e^{2x)}

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(dy)/(dx)+2y=2e^x

\frac{d y}{d x} + 2 y = 2 e^{x}

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

Solution steps

\frac{d y}{d x} + 2 y = 2 e^{x}

Solve linear ODE:

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

y = \frac{2 e ^{x}}{3} + \frac{c _{1}}{e ^{2 x}}

\frac{d}{d x} (x^{2} 10 x - 3)

3 y^{^{''}} + 17 y^{^{'}} + 10 y = 0

\frac{d}{d x} (m x^{m - 2} (m - 1))

y = e^{x}, y = e^{- 3 x}, x = ln (6)

\frac{d y}{d t} = t^{2} + 13 t^{2} y

What is the solution for (dy)/(dx)+2y=2e^x ?
The solution for (dy)/(dx)+2y=2e^x is y=(2e^x)/3+(c_{1})/(e^{2x)}