What is (\partial)/(\partial x)(2x^2+4y+1) ?

The answer to (\partial)/(\partial x)(2x^2+4y+1) is 4x

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(\partial)/(\partial x)(2x^2+4y+1)

\frac{\partial}{\partial x} (2 x^{2} + 4 y + 1)

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + 4 y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (4 y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (4 y) = 0

\frac{\partial}{\partial x} (1) = 0

= 4 x + 0 + 0

Simplify

= 4 x

f (x) = \frac{1}{2} ln (x)

\int \frac{3 x - x ^{3} + 1}{x ^{4}} d x

x \to 10 lim (ln (100 - x^{2}))

x^{2} + 1

x \to 0 - lim (\frac{sin ( 2 x )}{x})

What is (\partial)/(\partial x)(2x^2+4y+1) ?
The answer to (\partial)/(\partial x)(2x^2+4y+1) is 4x