What is the derivative of sin^2(x-3y) ?

The derivative of sin^2(x-3y) is 2sin(x-3y)cos(x-3y)(1-3(dy)/(dx))

What is the first derivative of sin^2(x-3y) ?

The first derivative of sin^2(x-3y) is 2sin(x-3y)cos(x-3y)(1-3(dy)/(dx))

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\frac{d}{d x} (sin^{2} (x - 3 y))

2 sin (x - 3 y) cos (x - 3 y) (1 - 3 \frac{d y}{d x})

Solution steps

\frac{d}{d x} (sin^{2} (x - 3 y))

Apply the chain rule:

2 sin (x - 3 y) \frac{d}{d x} (sin (x - 3 y))

= 2 sin (x - 3 y) \frac{d}{d x} (sin (x - 3 y))

\frac{d}{d x} (sin (x - 3 y)) = cos (x - 3 y) (1 - 3 \frac{d y}{d x})

= 2 sin (x - 3 y) cos (x - 3 y) (1 - 3 \frac{d y}{d x})

\int e^{x} 3 - e^{x} d x

\int 3 (x - 1) y^{3} e^{y (1 - x)} d x

\int + e^{- 0.1 x} d x

x \to 1 lim (ln (x^{\frac{1}{2}}))

\frac{1}{s ^{3} + 5 s}

What is the derivative of sin^2(x-3y) ?
The derivative of sin^2(x-3y) is 2sin(x-3y)cos(x-3y)(1-3(dy)/(dx))
What is the first derivative of sin^2(x-3y) ?
The first derivative of sin^2(x-3y) is 2sin(x-3y)cos(x-3y)(1-3(dy)/(dx))