What is the solution for dy=(y-1)^2dx ?

The solution for dy=(y-1)^2dx is y=-1/(x+c_{1)}+x/(x+c_{1)}+(c_{1})/(x+c_{1)}

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dy=(y-1)^2dx

d y = (y - 1)^{2} d x

y = - \frac{1}{x + c _{1}} + \frac{x}{x + c _{1}} + \frac{c _{1}}{x + c _{1}}

Solution steps

d y = (y - 1)^{2} d x

Solve separable ODE:

y = - \frac{1}{x + c _{1}} + \frac{x}{x + c _{1}} + \frac{c _{1}}{x + c _{1}}

y = - \frac{1}{x + c _{1}} + \frac{x}{x + c _{1}} + \frac{c _{1}}{x + c _{1}}

x \to 2 lim (\frac{x ^{2} - 4 x - 2 x}{2 x + 5})

y^{^{'}} - y^{2} + 0.5 - 20 y = 0

f (x) = 3 x^{4} - 65 x^{3}

x^{2} d x + 2 y d y = 0

\frac{s}{s ^{2} + 6 s + 34}

What is the solution for dy=(y-1)^2dx ?
The solution for dy=(y-1)^2dx is y=-1/(x+c_{1)}+x/(x+c_{1)}+(c_{1})/(x+c_{1)}