What is the derivative of sin(kx) ?

The derivative of sin(kx) is cos(kx)k

What is the first derivative of sin(kx) ?

The first derivative of sin(kx) is cos(kx)k

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\frac{d}{d x} (sin (k x))

cos (k x) k

Solution steps

\frac{d}{d x} (sin (k x))

Apply the chain rule:

cos (k x) \frac{d}{d x} (k x)

= cos (k x) \frac{d}{d x} (k x)

\frac{d}{d x} (k x) = k

= cos (k x) k

\frac{d}{d x} (\frac{2}{( 4 - x ) ^{2}})

\int 2 u^{2} d u

x \to - 1 lim (\frac{x - 1}{x + 1})

\int sin^{5} (\frac{x}{2}) d x

\frac{d}{d x} (x^{2} sin (ln (x)))

What is the derivative of sin(kx) ?
The derivative of sin(kx) is cos(kx)k
What is the first derivative of sin(kx) ?
The first derivative of sin(kx) is cos(kx)k