What is (\partial)/(\partial y)(2xy-y) ?

The answer to (\partial)/(\partial y)(2xy-y) is 2x-1

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(\partial)/(\partial y)(2xy-y)

\frac{\partial}{\partial y} (2 x y - y)

2 x - 1

Solution steps

\frac{\partial}{\partial y} (2 x y - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (y) = 1

= 2 x - 1

f (x) = \frac{7}{x}

\frac{sin ( x )}{cos ( x )}

\frac{d}{d t} (sin (3 ln (t) - e^{t^{2}}))

y = x^{2} - 3, (- 2, 1)

\int \frac{x ^{5} + 1}{x ^{3} - 3 x ^{2} - 10 x} d x

What is (\partial)/(\partial y)(2xy-y) ?
The answer to (\partial)/(\partial y)(2xy-y) is 2x-1