What is the d/(dt)((ln(t))^2) ?

The d/(dt)((ln(t))^2) is (2ln(t))/t

What is the first d/(dt)((ln(t))^2) ?

The first d/(dt)((ln(t))^2) is (2ln(t))/t

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\frac{d}{d t} ((ln (t))^{2})

\frac{2 ln ( t )}{t}

Solution steps

\frac{d}{d t} ((ln (t))^{2})

Apply the chain rule:

2 ln (t) \frac{d}{d t} (ln (t))

= 2 ln (t) \frac{d}{d t} (ln (t))

\frac{d}{d t} (ln (t)) = \frac{1}{t}

= 2 ln (t) \frac{1}{t}

Simplify

2 ln (t) \frac{1}{t} : \frac{2 ln ( t )}{t}

= \frac{2 ln ( t )}{t}

(1, - 1), (6, - 1)

\int_{6}^{8} \frac{92}{( x - 6 ) ^{3}} d x

\frac{d}{d x} (sin^{4} (cos (8 x)))

x \to 4 lim (x^{4} - 5 x^{2} + 2)

f (x) = \frac{1}{x}, [1, 2]