-2(dy)/(dx)+6x^2=0

Solución

- 2 \frac{d y}{d x} + 6 x^{2} = 0

y = x^{3} + c_{1}

Pasos de solución

- 2 \frac{d y}{d x} + 6 x^{2} = 0

Sustituir

\frac{d y}{d x}

with

y^{'} (x)

- 2 y^{^{'}} (x) + 6 x^{2} = 0

Despejar

y^{'} (x) : y^{'} (x) = 3 x^{2}

f^{^{'}} (x) = g (x)

entonces

f (x) = \int g (x) d x

y = \int 3 x^{2} d x

\int 3 x^{2} d x = x^{3} + c_{1}

y = x^{3} + c_{1}

\frac{\partial}{\partial x} (x^{2} y^{4})

x \to 0 lim (\frac{5 x ^{2}}{x})

\frac{\partial}{\partial x} (\frac{x}{4 x ^{2} + 9 y ^{2}})

y = \frac{x + 5}{x ^{3} + x - 9}

f (x) = \frac{6 x + x ^{2}}{( 3 + x ) ^{2}}