What is the sum from n=1 to infinity of (1+3/n)^n ?

The sum from n=1 to infinity of (1+3/n)^n is diverges

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sum from n=1 to infinity of (1+3/n)^n

n = 1 \sum \infty (1 + \frac{3}{n})^{n}

diverges

Solution steps

n = 1 \sum \infty (1 + \frac{3}{n})^{n}

Apply Series Divergence Test:

diverges

= diverges

x \to - 1 lim (\frac{x ^{3} - 1}{x - 1})

y = 5 x^{3} - 5 x, (1, 0)

n = 1 \sum \infty \frac{2 ^{n} x ^{n}}{n}

\int \frac{x ^{2}}{1 + x ^{2}} d x

\frac{d}{d x} (e^{x} + 3)

What is the sum from n=1 to infinity of (1+3/n)^n ?
The sum from n=1 to infinity of (1+3/n)^n is diverges