What is the tangent of y=5x^3-5x,(1,0) ?

The tangent of y=5x^3-5x,(1,0) is y=10x-10

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tangent of y=5x^3-5x,(1,0)

tangent of

y = 5 x^{3} - 5 x, (1, 0)

y = 10 x - 10

Solution steps

Find the slope of

y = 5 x^{3} - 5 x : \frac{d y}{d x} = 15 x^{2} - 5

Compute the slope of

y = 5 x^{3} - 5 x

(1, 0) : m = 10

Find the line with slope m=

10

and passing through

(1, 0) : y = 10 x - 10

y = 10 x - 10

n = 1 \sum \infty \frac{2 ^{n} x ^{n}}{n}

\int \frac{x ^{2}}{1 + x ^{2}} d x

\frac{d}{d x} (e^{x} + 3)

\int_{1}^{9} u + 2 d u

\int \frac{x ^{4} + 3 x ^{2} + 1}{x ^{5} + 5 x ^{3} + 5 x} d x

What is the tangent of y=5x^3-5x,(1,0) ?
The tangent of y=5x^3-5x,(1,0) is y=10x-10