What is (\partial)/(\partial y)(-xy^2) ?

The answer to (\partial)/(\partial y)(-xy^2) is -2xy

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(\partial)/(\partial y)(-xy^2)

\frac{\partial}{\partial y} (- x y^{2})

- 2 x y

Solution steps

\frac{\partial}{\partial y} (- x y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - x \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - x \cdot 2 y^{2 - 1}

Simplify

= - 2 x y

y = 2 x e^{- 6 x} - 4 e^{x^{3}}

f (x) = \frac{10 x}{x ^{2} - 6}, (4, 4)

4 x^{2} - 3

y = x^{2} + 4 x + 3

What is (\partial)/(\partial y)(-xy^2) ?
The answer to (\partial)/(\partial y)(-xy^2) is -2xy