What is the first derivative of 4x^2-3 ?

The first derivative of 4x^2-3 is 8x

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derivative of 4x^2-3

derivative of

4 x^{2} - 3

8 x

Solution steps

\frac{d}{d x} (4 x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3) = 0

= 8 x - 0

Simplify

= 8 x

y = x^{2} + 4 x + 3

n = 0 \sum \infty sin (\frac{1}{n ^{2}})

x \to 0 lim (\frac{\frac{1}{1 + x} - 1}{x})

ln (3 - x^{3})