What is the integral from 0 to 1 of 1/(x^{1/2)} ?

The integral from 0 to 1 of 1/(x^{1/2)} is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 1/(x^{1/2)}

\int_{0}^{1} \frac{1}{x ^{\frac{1}{2}}} d x

2

Solution steps

\int_{0}^{1} \frac{1}{x ^{\frac{1}{2}}} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{0}^{1}

= [2 x^{\frac{1}{2}}]_{0}^{1}

Compute the boundaries:

2

= 2

y^{^{'}} = - 10 y

\int_{0}^{\infty} e^{a x} d x

\frac{\partial}{\partial y} (x ln (5 x + 8 y))

\frac{x ^{2}}{x + 4}

f (x) = 3 x^{2} - 2 x, at x = - 1

What is the integral from 0 to 1 of 1/(x^{1/2)} ?
The integral from 0 to 1 of 1/(x^{1/2)} is 2