What is the derivative of ln(3-x^3) ?

The derivative of ln(3-x^3) is -(3x^2)/(3-x^3)

What is the first derivative of ln(3-x^3) ?

The first derivative of ln(3-x^3) is -(3x^2)/(3-x^3)

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derivative of

ln (3 - x^{3})

- \frac{3 x ^{2}}{3 - x ^{3}}

Solution steps

\frac{d}{d x} (ln (3 - x^{3}))

Apply the chain rule:

\frac{1}{3 - x ^{3}} \frac{d}{d x} (3 - x^{3})

= \frac{1}{3 - x ^{3}} \frac{d}{d x} (3 - x^{3})

\frac{d}{d x} (3 - x^{3}) = - 3 x^{2}

= \frac{1}{3 - x ^{3}} (- 3 x^{2})

Simplify

\frac{1}{3 - x ^{3}} (- 3 x^{2}) : - \frac{3 x ^{2}}{3 - x ^{3}}

= - \frac{3 x ^{2}}{3 - x ^{3}}

\int ln (x^{2} + x + 1) d x

\int 8 sec^{3} (x) d x

\frac{\partial}{\partial y} (x^{2} \cdot ln (y))

4 y^{^{''}} - 6 y^{^{'}} + 7 y = 15

\int 0 cos (x) d x

What is the derivative of ln(3-x^3) ?
The derivative of ln(3-x^3) is -(3x^2)/(3-x^3)
What is the first derivative of ln(3-x^3) ?
The first derivative of ln(3-x^3) is -(3x^2)/(3-x^3)