What is the limit as x approaches-1 of (x+3)/(x+1) ?

The limit as x approaches-1 of (x+3)/(x+1) is diverges

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limit as x approaches-1 of (x+3)/(x+1)

x \to - 1 lim (\frac{x + 3}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x + 3}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x + 3}{x + 1}) = \infty

x \to - 1 - lim (\frac{x + 3}{x + 1}) = - \infty

= diverges

\frac{d}{d z} (2^{z} lo g_{2} (z))

\frac{d}{d x} (\frac{x ^{2} - 3}{x ^{3}})

3 x^{^{'}} + 6 x = 4

\frac{r d θ}{d r} = θ^{2} + 1

f (x) = 5 - x^{2}, at x = 1

What is the limit as x approaches-1 of (x+3)/(x+1) ?
The limit as x approaches-1 of (x+3)/(x+1) is diverges