What is implicit 5x^2-4xy+3y^3=993 ?

The answer to implicit 5x^2-4xy+3y^3=993 is (dy)/(dx)=(-10x+4y)/(-4x+9y^2)

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implicit 5x^2-4xy+3y^3=993

implicit derivative

5 x^{2} - 4 x y + 3 y^{3} = 993

\frac{d y}{d x} = \frac{- 10 x + 4 y}{- 4 x + 9 y ^{2}}

Solution steps

5 x^{2} - 4 x y + 3 y^{3} = 993

Treat

y

y (x)

Differentiate both sides:

10 x - 4 (y + x \frac{d y}{d x}) + 9 y^{2} \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 10 x + 4 y}{- 4 x + 9 y ^{2}}

\frac{d y}{d x} = \frac{- 10 x + 4 y}{- 4 x + 9 y ^{2}}

x \to 6 lim (12)

f (x) = 3 x - 2 x^{2}

\frac{d}{d x} (25 I n (x^{2}) - x^{2})

n = 1 \sum \infty \frac{2 n + 1}{n}

\frac{5 x + 1}{x ^{2} - 3}

What is implicit 5x^2-4xy+3y^3=993 ?
The answer to implicit 5x^2-4xy+3y^3=993 is (dy)/(dx)=(-10x+4y)/(-4x+9y^2)