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Popular >

y^'+2xy=2x^3,y(0)=2

Solution

y^{^{'}} + 2 x y = 2 x^{3}, y (0) = 2

Solution

y = x^{2} - 1 + \frac{3}{e ^{x^{2}}}

Solution steps

y^{'} (x) + 2 x y = 2 x^{3}

Solve linear ODE:

y = x^{2} - 1 + \frac{3}{e ^{x^{2}}}

y = x^{2} - 1 + \frac{3}{e ^{x^{2}}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2xy=2x^3,y(0)=2 ?
The solution for y^'+2xy=2x^3,y(0)=2 is y=x^2-1+3/(e^{x^2)}