What is the integral from-1 to 2 of (2-5x+1/2 x^2) ?

The integral from-1 to 2 of (2-5x+1/2 x^2) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 2 of (2-5x+1/2 x^2)

\int_{- 1}^{2} (2 - 5 x + \frac{1}{2} x^{2}) d x

0

Solution steps

\int_{- 1}^{2} 2 - 5 x + \frac{1}{2} x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 d x - \int_{- 1}^{2} 5 x d x + \int_{- 1}^{2} \frac{1}{2} x^{2} d x

\int_{- 1}^{2} 2 d x = 6

\int_{- 1}^{2} 5 x d x = \frac{15}{2}

\int_{- 1}^{2} \frac{1}{2} x^{2} d x = \frac{3}{2}

= 6 - \frac{15}{2} + \frac{3}{2}

Simplify

6 - \frac{15}{2} + \frac{3}{2} : 0

= 0

f (x) = (x + 9)^{\frac{1}{2}}

f (x) = - x^{2} - x

\frac{d}{d x} ((ln (8))^{x})

\frac{\partial}{\partial x} (sin^{6} (3 x - 4 y))

\frac{d}{d y} ((4 - y)^{\frac{1}{3}})

What is the integral from-1 to 2 of (2-5x+1/2 x^2) ?
The integral from-1 to 2 of (2-5x+1/2 x^2) is 0