What is the integral of (e^{x+2})/(e^{x+1)} ?

The integral of (e^{x+2})/(e^{x+1)} is ex+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (e^{x+2})/(e^{x+1)}

\int \frac{e ^{x + 2}}{e ^{x + 1}} d x

e x + C

Solution steps

\int \frac{e ^{x + 2}}{e ^{x + 1}} d x

\frac{e ^{x + 2}}{e ^{x + 1}} = e

= \int e d x

Integral of a constant:

\int a d x = a x

= e x

Add a constant to the solution

= e x + C

18 cos (θ) + 9 sin^{2} (θ)

\frac{d ^{2}}{d x ^{2}} (5 e^{- x^{2}})

\frac{d}{d x} (\frac{1}{x} + \frac{1}{y})

f (x) = 5 e^{x} + x, at x = 0

\frac{d}{d x} (\frac{- e ^{- \frac{x}{2}} x + e ^{- \frac{x}{2}}}{2})

What is the integral of (e^{x+2})/(e^{x+1)} ?
The integral of (e^{x+2})/(e^{x+1)} is ex+C