What is the limit as x approaches 1-of 8/(x^3-1) ?

The limit as x approaches 1-of 8/(x^3-1) is -infinity

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limit as x approaches 1-of 8/(x^3-1)

x \to 1 - lim (\frac{8}{x ^{3} - 1})

- \infty

Solution steps

x \to 1 - lim (\frac{8}{x ^{3} - 1})

For

x

approaching

1

from the left

, x < 1 \Rightarrow x^{3} - 1 < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

\int e^{1.2 t} d t

\frac{d}{d x} (x^{2} sin^{2} (x))

\int + x^{3} sin (2 x) d x

\frac{d y}{d t} = t y^{2} + 2 y^{2}

y^{^{'}} - 3 y = 2 sin (3 x) - cos (3 x)

What is the limit as x approaches 1-of 8/(x^3-1) ?
The limit as x approaches 1-of 8/(x^3-1) is -infinity