What is the derivative of (2x+3)(3x-4) ?

The derivative of (2x+3)(3x-4) is 12x+1

What is the first derivative of (2x+3)(3x-4) ?

The first derivative of (2x+3)(3x-4) is 12x+1

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derivative of

(2 x + 3) (3 x - 4)

12 x + 1

Solution steps

\frac{d}{d x} ((2 x + 3) (3 x - 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x + 3, g = 3 x - 4

= \frac{d}{d x} (2 x + 3) (3 x - 4) + \frac{d}{d x} (3 x - 4) (2 x + 3)

\frac{d}{d x} (2 x + 3) = 2

\frac{d}{d x} (3 x - 4) = 3

= 2 (3 x - 4) + 3 (2 x + 3)

Simplify

2 (3 x - 4) + 3 (2 x + 3) : 12 x + 1

= 12 x + 1

\frac{5}{x ^{3}}

\int_{\frac{π}{9}}^{\infty} \frac{5}{x} d x

\frac{d}{d x} (x^{2} - 10 x)

y = 2 x^{2}, y = 2 x + 6, x = - 2

f (x) = (3 x - 2)^{2} (x^{5} - x^{2})^{3}

What is the derivative of (2x+3)(3x-4) ?
The derivative of (2x+3)(3x-4) is 12x+1
What is the first derivative of (2x+3)(3x-4) ?
The first derivative of (2x+3)(3x-4) is 12x+1