What is the derivative of arccos(4x) ?

The derivative of arccos(4x) is -4/(sqrt(1-16x^2))

What is the first derivative of arccos(4x) ?

The first derivative of arccos(4x) is -4/(sqrt(1-16x^2))

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derivative of

arccos (4 x)

- \frac{4}{1 - 16 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (4 x))

Apply the chain rule:

- \frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

= - \frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - \frac{1}{1 - ( 4 x ) ^{2}} \cdot 4

Simplify

- \frac{1}{1 - ( 4 x ) ^{2}} \cdot 4 : - \frac{4}{1 - 16 x ^{2}}

= - \frac{4}{1 - 16 x ^{2}}

\int \frac{x ^{3}}{x ^{4} + 7} d x

x \to 1 lim (arctan^{2} (x))

\frac{\partial}{\partial x} ((sin^{2} (x)) + y)

3 t - t^{2}

\frac{d}{d x} (cos (ln (sec (e^{- 2 x}))))

What is the derivative of arccos(4x) ?
The derivative of arccos(4x) is -4/(sqrt(1-16x^2))
What is the first derivative of arccos(4x) ?
The first derivative of arccos(4x) is -4/(sqrt(1-16x^2))