What is (\partial)/(\partial x)(9ye^{7x}) ?

The answer to (\partial)/(\partial x)(9ye^{7x}) is 63e^{7x}y

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(\partial)/(\partial x)(9ye^{7x})

\frac{\partial}{\partial x} (9 y e^{7 x})

63 e^{7 x} y

Solution steps

\frac{\partial}{\partial x} (9 y e^{7 x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 y \frac{\partial}{\partial x} (e^{7 x})

Apply the chain rule:

e^{7 x} \frac{\partial}{\partial x} (7 x)

= e^{7 x} \frac{\partial}{\partial x} (7 x)

\frac{\partial}{\partial x} (7 x) = 7

= 9 y e^{7 x} \cdot 7

Simplify

= 63 e^{7 x} y

\frac{x + 3}{x - 3}

\frac{\partial}{\partial y} (4 x + y)

7 t^{3}

\int \frac{e ^{x}}{( e ^{x} - 5 ) ( e ^{2 x} + 1 )} d x

\frac{\partial}{\partial y} (2 x^{2} y^{3})

What is (\partial)/(\partial x)(9ye^{7x}) ?
The answer to (\partial)/(\partial x)(9ye^{7x}) is 63e^{7x}y