What is (\partial)/(\partial y)(2x^2y^3) ?

The answer to (\partial)/(\partial y)(2x^2y^3) is 6x^2y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(2x^2y^3)

\frac{\partial}{\partial y} (2 x^{2} y^{3})

6 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial y} (2 x^{2} y^{3})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{2} \frac{\partial}{\partial y} (y^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2} \cdot 3 y^{3 - 1}

Simplify

= 6 x^{2} y^{2}

\frac{d}{d x} (2 x^{4} - 2 x)

\int \frac{4 x ^{2}}{1 - 8 x ^{3}} d x

\int (x - 3) (x^{2} - 6 x + 2)^{3} d x

\int_{0}^{6} e^{x} sin (x) d x

y = 2 x, (1, 3)

What is (\partial)/(\partial y)(2x^2y^3) ?
The answer to (\partial)/(\partial y)(2x^2y^3) is 6x^2y^2