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Popular >

derivative of sqrt(2x^4-2x)

Solution

\frac{d}{d x} (2 x^{4} - 2 x)

Solution

\frac{4 x ^{3} - 1}{2 x ^{4} - 2 x}

Solution steps

\frac{d}{d x} (2 x^{4} - 2 x)

Apply the chain rule:

\frac{1}{2 2 x ^{4} - 2 x} \frac{d}{d x} (2 x^{4} - 2 x)

= \frac{1}{2 2 x ^{4} - 2 x} \frac{d}{d x} (2 x^{4} - 2 x)

\frac{d}{d x} (2 x^{4} - 2 x) = 8 x^{3} - 2

= \frac{1}{2 2 x ^{4} - 2 x} (8 x^{3} - 2)

Simplify

\frac{1}{2 2 x ^{4} - 2 x} (8 x^{3} - 2) : \frac{4 x ^{3} - 1}{2 x ^{4} - 2 x}

= \frac{4 x ^{3} - 1}{2 x ^{4} - 2 x}

Popular Examples

integral of (4x^2)/(sqrt(1-8x^3))

\int \frac{4 x ^{2}}{1 - 8 x ^{3}} d x

integral of (x-3)(x^2-6x+2)^3

\int (x - 3) (x^{2} - 6 x + 2)^{3} d x

integral from 0 to 6 of e^xsin(x)

\int_{0}^{6} e^{x} sin (x) d x

area y=2x,(1,3)area

y = 2 x, (1, 3)

integral of sin(18x)cos(13x)

\int sin (18 x) cos (13 x) d x

Frequently Asked Questions (FAQ)

What is the derivative of sqrt(2x^4-2x) ?
The derivative of sqrt(2x^4-2x) is (4x^3-1)/(sqrt(2x^4-2x))
What is the first derivative of sqrt(2x^4-2x) ?
The first derivative of sqrt(2x^4-2x) is (4x^3-1)/(sqrt(2x^4-2x))