What is the solution for 2y^{''}-54y=0,y(1)=1,y(2)=2 ?

The solution for 2y^{''}-54y=0,y(1)=1,y(2)=2 is

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2y^{''}-54y=0,y(1)=1,y(2)=2

2 y^{^{''}} - 54 y = 0, y (1) = 1, y (2) = 2

y = (e^{33} - \frac{e ^{93} - 2 e ^{63}}{e ^{63} - 1}) e^{33 t - 63} + \frac{( e ^{93} - 2 e ^{63} ) e ^{- 33 t}}{e ^{63} - 1}

Solution steps

2 y^{''} (t) - 54 y = 0

Solve linear ODE:

y = (e^{33} - \frac{e ^{93} - 2 e ^{63}}{e ^{63} - 1}) e^{33 t - 63} + \frac{( e ^{93} - 2 e ^{63} ) e ^{- 33 t}}{e ^{63} - 1}

y = (e^{33} - \frac{e ^{93} - 2 e ^{63}}{e ^{63} - 1}) e^{33 t - 63} + \frac{( e ^{93} - 2 e ^{63} ) e ^{- 33 t}}{e ^{63} - 1}

x \to 0 lim (x (ln (x)))

\int_{0}^{4} x^{2} d x

\frac{d}{d y} (x + y)

\int x^{2} 2 - x d x

f (x) = \frac{x ( x ^{2} + 4 )}{x - 2}

What is the solution for 2y^{''}-54y=0,y(1)=1,y(2)=2 ?
The solution for 2y^{''}-54y=0,y(1)=1,y(2)=2 is