What is the integral from 0 to 4 of x^2 ?

The integral from 0 to 4 of x^2 is 64/3

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integral from 0 to 4 of x^2

\int_{0}^{4} x^{2} d x

\frac{64}{3}

Solution steps

\int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= \frac{64}{3}

\frac{d}{d y} (x + y)

\int x^{2} 2 - x d x

f (x) = \frac{x ( x ^{2} + 4 )}{x - 2}

\int 7 x^{- \frac{8}{9}} d x

\frac{y ^{^{'}}}{x ^{3} + y} = \frac{1}{x}

What is the integral from 0 to 4 of x^2 ?
The integral from 0 to 4 of x^2 is 64/3